Answer :
To determine the velocity of a ball falling with 100 joules of kinetic energy and a mass of 2 kilograms, we'll use the given formula:
[tex]\[ V = \sqrt{\frac{2 K B}{m}} \][/tex]
where:
- \( V \) is the velocity,
- \( K \) is the kinetic energy,
- \( m \) is the mass.
Given values:
[tex]\[ K = 100 \text{ joules} \][/tex]
[tex]\[ m = 2 \text{ kilograms} \][/tex]
Let's substitute these values into the formula:
[tex]\[ V = \sqrt{\frac{2 \times 100}{2}} \][/tex]
Simplifying inside the square root:
[tex]\[ V = \sqrt{\frac{200}{2}} \][/tex]
[tex]\[ V = \sqrt{100} \][/tex]
[tex]\[ V = 10 \text{ m/s} \][/tex]
Therefore, the velocity of the ball is:
E. [tex]\( 10 \text{ m/s} \)[/tex]
[tex]\[ V = \sqrt{\frac{2 K B}{m}} \][/tex]
where:
- \( V \) is the velocity,
- \( K \) is the kinetic energy,
- \( m \) is the mass.
Given values:
[tex]\[ K = 100 \text{ joules} \][/tex]
[tex]\[ m = 2 \text{ kilograms} \][/tex]
Let's substitute these values into the formula:
[tex]\[ V = \sqrt{\frac{2 \times 100}{2}} \][/tex]
Simplifying inside the square root:
[tex]\[ V = \sqrt{\frac{200}{2}} \][/tex]
[tex]\[ V = \sqrt{100} \][/tex]
[tex]\[ V = 10 \text{ m/s} \][/tex]
Therefore, the velocity of the ball is:
E. [tex]\( 10 \text{ m/s} \)[/tex]
