Answer :
Sure, let's go step by step to convert each given equation into an equation with two variables.
### (i) \(x = -5\)
Here, \(x\) is defined with no reference to \(y\). We can represent this equation as involving both \(x\) and \(y\) by indicating that the coefficient of \(y\) is zero. Therefore, the equation becomes:
[tex]\[ x + 0y = -5 \][/tex]
### (ii) \(y = 2\)
Similarly, here \(y\) is defined independently of \(x\). To include both variables, we assign \(x\) a coefficient of zero:
[tex]\[ 0x + y = 2 \][/tex]
### (iii) \(2x = 3\)
In this equation, \(x\) is related to a constant without \(y\). To convert it into a form involving both \(x\) and \(y\), we add the term \(0y\):
[tex]\[ 2x + 0y = 3 \][/tex]
### (iv) \(5y = 2\)
Lastly, here \(y\) is related to a constant and there is no \(x\) term. To write this with both variables, we add the term \(0x\):
[tex]\[ 0x + 5y = 2 \][/tex]
To summarize:
- \(x = -5\) becomes \(x + 0y = -5\).
- \(y = 2\) becomes \(0x + y = 2\).
- \(2x = 3\) becomes \(2x + 0y = 3\).
- [tex]\(5y = 2\)[/tex] becomes [tex]\(0x + 5y = 2\)[/tex].
### (i) \(x = -5\)
Here, \(x\) is defined with no reference to \(y\). We can represent this equation as involving both \(x\) and \(y\) by indicating that the coefficient of \(y\) is zero. Therefore, the equation becomes:
[tex]\[ x + 0y = -5 \][/tex]
### (ii) \(y = 2\)
Similarly, here \(y\) is defined independently of \(x\). To include both variables, we assign \(x\) a coefficient of zero:
[tex]\[ 0x + y = 2 \][/tex]
### (iii) \(2x = 3\)
In this equation, \(x\) is related to a constant without \(y\). To convert it into a form involving both \(x\) and \(y\), we add the term \(0y\):
[tex]\[ 2x + 0y = 3 \][/tex]
### (iv) \(5y = 2\)
Lastly, here \(y\) is related to a constant and there is no \(x\) term. To write this with both variables, we add the term \(0x\):
[tex]\[ 0x + 5y = 2 \][/tex]
To summarize:
- \(x = -5\) becomes \(x + 0y = -5\).
- \(y = 2\) becomes \(0x + y = 2\).
- \(2x = 3\) becomes \(2x + 0y = 3\).
- [tex]\(5y = 2\)[/tex] becomes [tex]\(0x + 5y = 2\)[/tex].
