Parallel lines e and f are cut by transversal b.

Horizontal and parallel lines e and f are cut by transversal b. At the intersection of lines b and e, the uppercase right angle is (2 x + 18) degrees. At the intersection of lines b and f, the top right angle is (4 x minus 14) degrees and the bottom right angle is y degrees.

What is the value of y?

16
50
130
164



Answer :

Answer:

130

Step-by-step explanation:

Solving the Problem

Visualize the Problem

We can start by drawing two parallel lines and a diagonal line cutting through them, and labelling them accordingly.

Then, we can label the top right angles in each intersection (2x + 18) and (4x - 14) respectively.

Lastly, label "y" to the bottom right angle at the intersection of lines b and f.

(See attached image)

[tex]\dotfill[/tex]

Angles

Recalling our knowledge of the types of angles made by parallel lines and a transversal, we can identify that (2x + 18) and (4x - 14) are corresponding angles, thus having the same measure.

Additionally, we can identify that angles (4x - 14) and y are supplementary, or have a sum of 180 degrees.

[tex]\dotfill[/tex]

Synthesize and Solve

We can set a system of equations to find our final answer,

  • (2x + 18) and (4x - 14) to be equal to each other: 2x + 18 = 4x - 14,
  • set an equation that sums (4x - 14) and y to 180: (4x - 14) + y = 180.

                     

                                  2x + 18 = 4x - 14

                                  18 = 4x - 2x - 14  (add 2x both sides)

                                    18 = 2x - 14  (simplify right side)

                                        32 = 2x  (add 14 both sides)

                                          16 = x  (divide by 2)

We can plug the value of x into the second equation.

                                4x - 14 + y = 180

                               4(16) - 14 + y = 180

                                64 - 14 + y = 180

                                   50 + y = 180

                                      y = 130

View image zarahaider4211

Other Questions