The augmented matrix is in row-echelon form. Assume that the variables are \( x, y, \) and \( z \) and use back substitution to obtain the solution of the associated system of linear equations.

[tex]\[
\left[\begin{array}{rrr|c}
1 & -\frac{1}{4} & -\frac{1}{4} & \frac{13}{4} \\
0 & 1 & -\frac{7}{2} & \frac{17}{2} \\
0 & 0 & 1 & -3
\end{array}\right]
\][/tex]

Select the correct choice below and, if necessary, fill in the answer box(es) to complete your choice.

A. There is one solution. The solution set is \(\{\ \square, \square, \square \ \}\).
(Simplify your answer. Type an ordered triple, using integers or fractions.)

B. There are infinitely many solutions. The solution set is the set of all ordered triples \(\{( \square, \square, z)\}\), where \( z \) is any real number.
(Type expressions using \( z \) as the variable. Simplify your answers.)

C. The system is inconsistent. The solution set is [tex]\(\varnothing\)[/tex].