Jaolen's new toy car can move [tex]$4 \frac{1}{4}$[/tex] feet in [tex]$\frac{2}{3}$[/tex] of a second. How far could it go in 6 seconds?



Answer :

To determine how far Jaolen's new toy car can go in 6 seconds, we can follow these steps:

1. Convert Mixed Fraction to Decimal:
Jaolen's toy car moves [tex]\(4 \frac{1}{4}\)[/tex] feet. First, we need to convert this mixed fraction to a decimal.
[tex]\[ 4 \frac{1}{4} = 4 + \frac{1}{4} = 4.25 \text{ feet} \][/tex]

2. Identify the Time Interval:
The toy car covers this distance in [tex]\(\frac{2}{3}\)[/tex] second.

3. Calculate the Speed:
We need to calculate the speed of the toy car in feet per second. The speed [tex]\( v \)[/tex] is given by dividing the distance by the time:
[tex]\[ v = \frac{\text{distance}}{\text{time}} = \frac{4.25 \text{ feet}}{\frac{2}{3} \text{ second}} \][/tex]

Dividing by a fraction is the same as multiplying by its reciprocal. So we have:
[tex]\[ v = 4.25 \times \frac{3}{2} = 4.25 \times 1.5 = 6.375 \text{ feet per second} \][/tex]

4. Calculate the Total Distance in 6 Seconds:
We now know that the speed of the toy car is [tex]\(6.375\)[/tex] feet per second. To find out how far it can go in 6 seconds, we multiply the speed by the total time:
[tex]\[ \text{Distance} = \text{Speed} \times \text{Time} = 6.375 \text{ feet/second} \times 6 \text{ seconds} = 38.25 \text{ feet} \][/tex]

Therefore, Jaolen's toy car could go 38.25 feet in 6 seconds.

Other Questions