What is the equation of the line that passes through the point [tex](-6, 5)[/tex] and has a slope of [tex]-\frac{1}{6}[/tex]?

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Answer :

To find the equation of the line that passes through the point [tex]\((-6, 5)\)[/tex] and has a slope of [tex]\(-\frac{1}{6}\)[/tex], we can follow these steps:

1. Identify the given information:
- Point: [tex]\((-6, 5)\)[/tex]
- Slope: [tex]\(m = -\frac{1}{6}\)[/tex]

2. Determine which form of the line equation to use:
We will use the point-slope form of the line equation, which is:
[tex]\[ y - y_1 = m(x - x_1) \][/tex]
Here, [tex]\((x_1, y_1)\)[/tex] is the point through which the line passes, and [tex]\(m\)[/tex] is the slope.

3. Substitute the given point and slope into the point-slope form:
[tex]\[ y - 5 = -\frac{1}{6}(x + 6) \][/tex]

4. Simplify the equation to get it into the slope-intercept form [tex]\(y = mx + b\)[/tex]:
[tex]\[ y - 5 = -\frac{1}{6}(x + 6) \][/tex]
Distribute the slope [tex]\(-\frac{1}{6}\)[/tex]:
[tex]\[ y - 5 = -\frac{1}{6}x - 1 \][/tex]

5. Solve for [tex]\(y\)[/tex] to find the y-intercept [tex]\(b\)[/tex]:
Add 5 to both sides to isolate [tex]\(y\)[/tex]:
[tex]\[ y = -\frac{1}{6}x - 1 + 5 \][/tex]
Combine like terms:
[tex]\[ y = -\frac{1}{6}x + 4 \][/tex]

6. Write down the final equation:
The equation of the line in slope-intercept form [tex]\(y = mx + b\)[/tex] is:
[tex]\[ y = -\frac{1}{6}x + 4 \][/tex]

So, the equation of the line that passes through the point [tex]\((-6, 5)\)[/tex] and has a slope of [tex]\(-\frac{1}{6}\)[/tex] is:
[tex]\[ y = -\frac{1}{6}x + 4 \][/tex]

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