Answer :
Let's analyze the given data and derive the required percentages to determine which statement is true.
We have the following information from the school:
- For the first lunch period, [tex]\( 17 \% \)[/tex] of students eat outside, and [tex]\( 38 \% \)[/tex] eat inside. The total percentage of students in the first lunch period is [tex]\( 55 \% \)[/tex].
- For the second lunch period, [tex]\( 21 \% \)[/tex] of students eat outside, and [tex]\( 24 \% \)[/tex] eat inside. The total percentage of students in the second lunch period is [tex]\( 45 \% \)[/tex].
From this data, we can use the total percentages to find the actual percentage of students eating outside in both lunch periods.
First, let's find the given percentage of first-lunch students who eat outside:
[tex]\[ \text{Percentage of first-lunch students eating outside} = \frac{17}{55} \times 100 \approx 30.91 \% \][/tex]
Similarly, we need to find the percentage of second-lunch students who eat outside:
[tex]\[ \text{Percentage of second-lunch students eating outside} = \frac{21}{45} \times 100 \approx 46.67 \% \][/tex]
Now we compare these percentages with the provided statements:
1. Statement A: [tex]\( 21 \% \)[/tex] of second-lunch students eat outside.
2. Statement B: [tex]\( 47 \% \)[/tex] of second-lunch students eat outside.
3. Statement C: [tex]\( 24 \% \)[/tex] of second-lunch students eat outside.
4. Statement D: [tex]\( 45 \% \)[/tex] of second-lunch students eat outside.
By examining the percentages calculated:
- The percentage of first-lunch students eating outside is approximately [tex]\( 30.91 \% \)[/tex].
- The percentage of second-lunch students eating outside is approximately [tex]\( 46.67 \% \)[/tex].
Upon reviewing the given statements, none of them exactly match [tex]\( 46.67 \% \)[/tex], so none of the given statements (A, B, C, or D) are true based on our calculations. Thus, the answer is that none of the provided statements accurately represent the situation.
Hence, none of the statements (A, B, C, or D) are true.
We have the following information from the school:
- For the first lunch period, [tex]\( 17 \% \)[/tex] of students eat outside, and [tex]\( 38 \% \)[/tex] eat inside. The total percentage of students in the first lunch period is [tex]\( 55 \% \)[/tex].
- For the second lunch period, [tex]\( 21 \% \)[/tex] of students eat outside, and [tex]\( 24 \% \)[/tex] eat inside. The total percentage of students in the second lunch period is [tex]\( 45 \% \)[/tex].
From this data, we can use the total percentages to find the actual percentage of students eating outside in both lunch periods.
First, let's find the given percentage of first-lunch students who eat outside:
[tex]\[ \text{Percentage of first-lunch students eating outside} = \frac{17}{55} \times 100 \approx 30.91 \% \][/tex]
Similarly, we need to find the percentage of second-lunch students who eat outside:
[tex]\[ \text{Percentage of second-lunch students eating outside} = \frac{21}{45} \times 100 \approx 46.67 \% \][/tex]
Now we compare these percentages with the provided statements:
1. Statement A: [tex]\( 21 \% \)[/tex] of second-lunch students eat outside.
2. Statement B: [tex]\( 47 \% \)[/tex] of second-lunch students eat outside.
3. Statement C: [tex]\( 24 \% \)[/tex] of second-lunch students eat outside.
4. Statement D: [tex]\( 45 \% \)[/tex] of second-lunch students eat outside.
By examining the percentages calculated:
- The percentage of first-lunch students eating outside is approximately [tex]\( 30.91 \% \)[/tex].
- The percentage of second-lunch students eating outside is approximately [tex]\( 46.67 \% \)[/tex].
Upon reviewing the given statements, none of them exactly match [tex]\( 46.67 \% \)[/tex], so none of the given statements (A, B, C, or D) are true based on our calculations. Thus, the answer is that none of the provided statements accurately represent the situation.
Hence, none of the statements (A, B, C, or D) are true.
