Solve [tex]\( |x| + 7 \ \textless \ 4 \)[/tex]

A. [tex]\(\{x \mid x \ \textless \ -11 \text{ or } x \ \textgreater \ -3\}\)[/tex]

B. [tex]\(\varnothing\)[/tex]

C. [tex]\(\{x \mid -3 \ \textless \ x \ \textless \ 3\}\)[/tex]



Answer :

Certainly! Let's solve the inequality [tex]\( |x| + 7 < 4 \)[/tex] step by step.

1. Isolate the absolute value term:
[tex]\[ |x| + 7 < 4 \][/tex]

2. Subtract 7 from both sides:
[tex]\[ |x| < 4 - 7 \][/tex]

3. Simplify the right side:
[tex]\[ |x| < -3 \][/tex]

4. Interpret the result:
The expression [tex]\( |x| < -3 \)[/tex] seems problematic because the absolute value of any real number is always non-negative (i.e., [tex]\( |x| \geq 0 \)[/tex] for all [tex]\( x \)[/tex]). There is no real number [tex]\( x \)[/tex] such that its absolute value is less than a negative number. In this case, [tex]\( -3 \)[/tex] is a negative number, and thus the inequality [tex]\( |x| < -3 \)[/tex] is impossible to satisfy for any real number.

Therefore, the solution set for the inequality [tex]\( |x| + 7 < 4 \)[/tex] is the empty set, denoted by [tex]\( \varnothing \)[/tex].

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