Divide [tex]$12x^3 - 6x^2 - 3x$[/tex] by [tex]$-3x$[/tex].

A. [tex]-4x^3 - 2x^2 - x[/tex]
B. [tex]-4x^2 + 2x[/tex]
C. [tex]-4x^2 + 2x - 1[/tex]
D. [tex]-4x^2 + 2x + 1[/tex]



Answer :

To divide the polynomial [tex]\(12x^3 - 6x^2 - 3x\)[/tex] by [tex]\(-3x\)[/tex], follow these steps carefully:

1. Set up the division: We start with the polynomial [tex]\(12x^3 - 6x^2 - 3x\)[/tex] and we are dividing it by [tex]\(-3x\)[/tex].

2. Divide the first term:
[tex]\[ \frac{12x^3}{-3x} = -4x^2 \][/tex]
Write [tex]\(-4x^2\)[/tex] as the first term of the quotient.

3. Multiply and subtract:
Multiply [tex]\(-4x^2\)[/tex] by [tex]\(-3x\)[/tex]:
[tex]\[ -4x^2 \cdot (-3x) = 12x^3 \][/tex]
Subtract [tex]\(12x^3\)[/tex] from [tex]\(12x^3 - 6x^2 - 3x\)[/tex]:
[tex]\[ (12x^3 - 6x^2 - 3x) - 12x^3 = -6x^2 - 3x \][/tex]

4. Divide the next term:
[tex]\[ \frac{-6x^2}{-3x} = 2x \][/tex]
Write [tex]\(2x\)[/tex] as the next term of the quotient.

5. Multiply and subtract:
Multiply [tex]\(2x\)[/tex] by [tex]\(-3x\)[/tex]:
[tex]\[ 2x \cdot (-3x) = -6x^2 \][/tex]
Subtract [tex]\(-6x^2\)[/tex] from [tex]\(-6x^2 - 3x\)[/tex]:
[tex]\[ (-6x^2 - 3x) - (-6x^2) = -3x \][/tex]

6. Divide the next term:
[tex]\[ \frac{-3x}{-3x} = 1 \][/tex]
Write [tex]\(1\)[/tex] as the next term of the quotient.

7. Multiply and subtract:
Multiply [tex]\(1\)[/tex] by [tex]\(-3x\)[/tex]:
[tex]\[ 1 \cdot (-3x) = -3x \][/tex]
Subtract [tex]\(-3x\)[/tex] from [tex]\(-3x\)[/tex]:
[tex]\[ -3x - (-3x) = 0 \][/tex]

Since we have no remainder left after the final subtraction, the quotient of the division is:
[tex]\[ -4x^2 + 2x + 1 \][/tex]

So, the quotient is [tex]\(-4x^2 + 2x + 1\)[/tex] and the remainder is [tex]\(0\)[/tex].

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