Answer :
To determine the probability that the child will not have color-deficient vision with the given parent genotypes [tex]\( X^R X \times X^R Y \)[/tex], we need to perform a Punnett square analysis for these genotypes.
1. Identify the parent genotypes:
- Parent 1 (female): [tex]\( X^R X \)[/tex]
- Parent 2 (male): [tex]\( X^R Y \)[/tex]
2. Set up the Punnett square:
[tex]\[ \begin{array}{c|c|c} & X^R & Y \\ \hline X^R & X^R X^R & X^R Y \\ X & X X^R & X Y \\ \end{array} \][/tex]
In this Punnett square, we combine the possible gametes from each parent.
3. List the possible offspring genotypes:
- [tex]\( X^R X^R \)[/tex]
- [tex]\( X^R Y \)[/tex]
- [tex]\( X X^R \)[/tex]
- [tex]\( X Y \)[/tex]
4. Determine the probability of offspring not having color-deficient vision:
- [tex]\( X^R X^R \)[/tex]: Female child, not color-deficient because it has at least one [tex]\( X^R \)[/tex] allele.
- [tex]\( X^R Y \)[/tex]: Male child, not color-deficient because it has the [tex]\( X^R \)[/tex] allele.
- [tex]\( X X^R \)[/tex]: Female child, not color-deficient because it has the [tex]\( X^R \)[/tex] allele.
- [tex]\( X Y \)[/tex]: Male child, color-deficient because it does not have the [tex]\( X^R \)[/tex] allele.
5. Count the number of offspring that are not color-deficient:
- [tex]\( X^R X^R \)[/tex]
- [tex]\( X^R Y \)[/tex]
- [tex]\( X X^R \)[/tex]
Therefore, 3 out of the 4 possible genotypes do not have color-deficient vision.
6. Calculate the probability:
[tex]\[ \frac{3}{4} = 0.75 \][/tex]
Thus, the probability that the child will not have color-deficient vision is [tex]\(0.75\)[/tex], making the correct answer:
A. 0.75
1. Identify the parent genotypes:
- Parent 1 (female): [tex]\( X^R X \)[/tex]
- Parent 2 (male): [tex]\( X^R Y \)[/tex]
2. Set up the Punnett square:
[tex]\[ \begin{array}{c|c|c} & X^R & Y \\ \hline X^R & X^R X^R & X^R Y \\ X & X X^R & X Y \\ \end{array} \][/tex]
In this Punnett square, we combine the possible gametes from each parent.
3. List the possible offspring genotypes:
- [tex]\( X^R X^R \)[/tex]
- [tex]\( X^R Y \)[/tex]
- [tex]\( X X^R \)[/tex]
- [tex]\( X Y \)[/tex]
4. Determine the probability of offspring not having color-deficient vision:
- [tex]\( X^R X^R \)[/tex]: Female child, not color-deficient because it has at least one [tex]\( X^R \)[/tex] allele.
- [tex]\( X^R Y \)[/tex]: Male child, not color-deficient because it has the [tex]\( X^R \)[/tex] allele.
- [tex]\( X X^R \)[/tex]: Female child, not color-deficient because it has the [tex]\( X^R \)[/tex] allele.
- [tex]\( X Y \)[/tex]: Male child, color-deficient because it does not have the [tex]\( X^R \)[/tex] allele.
5. Count the number of offspring that are not color-deficient:
- [tex]\( X^R X^R \)[/tex]
- [tex]\( X^R Y \)[/tex]
- [tex]\( X X^R \)[/tex]
Therefore, 3 out of the 4 possible genotypes do not have color-deficient vision.
6. Calculate the probability:
[tex]\[ \frac{3}{4} = 0.75 \][/tex]
Thus, the probability that the child will not have color-deficient vision is [tex]\(0.75\)[/tex], making the correct answer:
A. 0.75
