A triangle has vertices at [tex]$B (-3, 0)$[/tex], [tex]$C (2, -1)$[/tex], and [tex]$D (-1, 2)$[/tex]. Which transformation would produce an image with vertices [tex]$B^{\prime}(-2, 1)$[/tex], [tex]$C^{\prime}(3, 2)$[/tex], and [tex]$D^{\prime}(0, -1)$[/tex]?

A. [tex]\((x, y) \rightarrow (x, -y) \rightarrow (x + 1, y + 1)\)[/tex]

B. [tex]\((x, y) \rightarrow (-x, y) \rightarrow (x + 1, y + 1)\)[/tex]

C. [tex]\((x, y) \rightarrow (x, -y) \rightarrow (x + 2, y + 2)\)[/tex]

D. [tex]\((x, y) \rightarrow (-x, y) \rightarrow (x + 2, y + 2)\)[/tex]



Answer :

To determine which transformation produces the specified image of the triangle's vertices, we need to evaluate each transformation step-by-step and check if it matches the given image vertices [tex]\( B' (-2,1), C' (3,2), D' (0,-1) \)[/tex].

1. First Transformation:
[tex]\[ (x, y) \rightarrow (x, -y) \rightarrow (x+1, y+1) \][/tex]

- Apply [tex]\( (x, y) \rightarrow (x, -y) \)[/tex]:
- Vertex [tex]\( B (-3, 0) \)[/tex] becomes [tex]\( (-3, 0) \)[/tex].
- Vertex [tex]\( C (2, -1) \)[/tex] becomes [tex]\( (2, 1) \)[/tex].
- Vertex [tex]\( D (-1, 2) \)[/tex] becomes [tex]\( (-1, -2) \)[/tex].

- Apply [tex]\( (x, y) \rightarrow (x+1, y+1) \)[/tex]:
- Resulting [tex]\( (-3, 0) \)[/tex] becomes [tex]\( (-2, 1) \)[/tex].
- Resulting [tex]\( (2, 1) \)[/tex] becomes [tex]\( (3, 2) \)[/tex].
- Resulting [tex]\( (-1, -2) \)[/tex] becomes [tex]\( (0, -1) \)[/tex].

The transformed vertices are [tex]\( B'(-2, 1), C'(3, 2), D'(0, -1) \)[/tex]. This matches the given image vertices.

2. Second Transformation:
[tex]\[ (x, y) \rightarrow (-x, y) \rightarrow (x+1, y+1) \][/tex]

- Apply [tex]\( (x, y) \rightarrow (-x, y) \)[/tex]:
- Vertex [tex]\( B(-3, 0) \)[/tex] becomes [tex]\( (3, 0) \)[/tex].
- Vertex [tex]\( C(2, -1) \)[/tex] becomes [tex]\( (-2, -1) \)[/tex].
- Vertex [tex]\( D(-1, 2) \)[/tex] becomes [tex]\( (1, 2) \)[/tex].

- Apply [tex]\( (x, y) \rightarrow (x+1, y+1) \)[/tex]:
- Resulting [tex]\( (3, 0) \)[/tex] becomes [tex]\( (4, 1) \)[/tex].
- Resulting [tex]\( (-2, -1) \)[/tex] becomes [tex]\( (-1, 0) \)[/tex].
- Resulting [tex]\( (1, 2) \)[/tex] becomes [tex]\( (2, 3) \)[/tex].

The transformed vertices do not match the given image vertices.

3. Third Transformation:
[tex]\[ (x, y) \rightarrow (x, -y) \rightarrow (x+2, y+2) \][/tex]

- Apply [tex]\( (x, y) \rightarrow (x, -y) \)[/tex]:
- Vertex [tex]\( B(-3, 0) \)[/tex] remains [tex]\( (-3, 0) \)[/tex].
- Vertex [tex]\( C(2, -1) \)[/tex] becomes [tex]\( (2, 1) \)[/tex].
- Vertex [tex]\( D(-1, 2) \)[/tex] becomes [tex]\( (-1, -2) \)[/tex].

- Apply [tex]\( (x, y) \rightarrow (x+2, y+2) \)[/tex]:
- Resulting [tex]\( (-3, 0) \)[/tex] becomes [tex]\( (-1, 2) \)[/tex].
- Resulting [tex]\( (2, 1) \)[/tex] becomes [tex]\( (4, 3) \)[/tex].
- Resulting [tex]\( (-1, -2) \)[/tex] becomes [tex]\( (1, 0) \)[/tex].

The transformed vertices do not match the given image vertices.

4. Fourth Transformation:
[tex]\[ (x, y) \rightarrow (-x, y) \rightarrow (x + 2, y + 2) \][/tex]

- Apply [tex]\( (x, y) \rightarrow (-x, y) \)[/tex]:
- Vertex [tex]\( B(-3, 0) \)[/tex] becomes [tex]\( (3, 0) \)[/tex].
- Vertex [tex]\( C(2, -1) \)[/tex] becomes [tex]\( (-2, -1) \)[/tex].
- Vertex [tex]\( D(-1, 2) \)[/tex] becomes [tex]\( (1, 2) \)[/tex].

- Apply [tex]\( (x, y) \rightarrow (x+2, y+2) \)[/tex]:
- Resulting [tex]\( (3, 0) \)[/tex] becomes [tex]\( (5, 2) \)[/tex].
- Resulting [tex]\( (-2, -1) \)[/tex] becomes [tex]\( (0, 1) \)[/tex].
- Resulting [tex]\( (1, 2) \)[/tex] becomes [tex]\( (3, 4) \)[/tex].

The transformed vertices do not match the given image vertices.

Based on the above steps, the only transformation that matches the given image vertices is:
[tex]\[ (x, y) \rightarrow (x, -y) \rightarrow (x+1, y+1) \][/tex]

Thus, the correct transformation is:
[tex]\[ (x, y) \rightarrow (x, -y) \rightarrow (x+1, y+1) \][/tex]

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