Solve for [tex]\( x \)[/tex]:

[tex]\[ 3x = 6x - 2 \][/tex]

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Format the following question or task so that it is easier to read. Fix any grammar or spelling errors. Remove phrases that are not part of the question. Do not remove or change LaTeX formatting. Do not change or remove [tex] [/tex] tags. If the question is nonsense, rewrite it so that it makes sense.

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[tex]\[ x^2 + 7x + 12 = 0 \][/tex]



Answer :

To solve the quadratic expression [tex]\(x^2 + 7x + 12\)[/tex], we start by recognizing that it is a quadratic equation of the form [tex]\(ax^2 + bx + c\)[/tex], where [tex]\(a = 1\)[/tex], [tex]\(b = 7\)[/tex], and [tex]\(c = 12\)[/tex].

Next, we look for two numbers that multiply to [tex]\(ac\)[/tex] (which is [tex]\(1 \times 12 = 12\)[/tex]) and add up to [tex]\(b\)[/tex] (which is [tex]\(7\)[/tex]). These numbers are [tex]\(3\)[/tex] and [tex]\(4\)[/tex], since:

[tex]\[ 3 \cdot 4 = 12 \][/tex]
[tex]\[ 3 + 4 = 7 \][/tex]

We can then factor the quadratic expression as follows:

[tex]\[ x^2 + 7x + 12 = (x + 3)(x + 4) \][/tex]

To verify that this factorization is correct, we can expand [tex]\( (x + 3)(x + 4) \)[/tex] and check if it equals the original quadratic expression:

[tex]\[ (x + 3)(x + 4) = x(x + 4) + 3(x + 4) \][/tex]
[tex]\[ = x^2 + 4x + 3x + 12 \][/tex]
[tex]\[ = x^2 + 7x + 12 \][/tex]

This confirms that the factorization is accurate. Thus, the given quadratic expression [tex]\( x^2 + 7x + 12 \)[/tex] can be expressed as the product of two binomials:

[tex]\[ x^2 + 7x + 12 = (x + 3)(x + 4) \][/tex]

That is the detailed, step-by-step solution for the given quadratic expression.

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