Answer :
To solve the equation [tex]\( 3(c x - 7) = 9 \)[/tex] for [tex]\( x \)[/tex], follow these steps:
1. Distribute the 3 on the left-hand side of the equation:
[tex]\[ 3(c x - 7) = 3 \cdot (c x) - 3 \cdot 7 = 3 c x - 21 \][/tex]
Thus the equation becomes:
[tex]\[ 3 c x - 21 = 9 \][/tex]
2. Isolate the term with [tex]\( x \)[/tex]. To do this, first add 21 to both sides of the equation to move the constant term:
[tex]\[ 3 c x - 21 + 21 = 9 + 21 \][/tex]
[tex]\[ 3 c x = 30 \][/tex]
3. Solve for [tex]\( x \)[/tex] by dividing both sides of the equation by [tex]\( 3c \)[/tex]:
[tex]\[ x = \frac{30}{3 c} = \frac{10}{c} \][/tex]
So, the value of [tex]\( x \)[/tex] in the equation is [tex]\( \frac{10}{c} \)[/tex].
1. Distribute the 3 on the left-hand side of the equation:
[tex]\[ 3(c x - 7) = 3 \cdot (c x) - 3 \cdot 7 = 3 c x - 21 \][/tex]
Thus the equation becomes:
[tex]\[ 3 c x - 21 = 9 \][/tex]
2. Isolate the term with [tex]\( x \)[/tex]. To do this, first add 21 to both sides of the equation to move the constant term:
[tex]\[ 3 c x - 21 + 21 = 9 + 21 \][/tex]
[tex]\[ 3 c x = 30 \][/tex]
3. Solve for [tex]\( x \)[/tex] by dividing both sides of the equation by [tex]\( 3c \)[/tex]:
[tex]\[ x = \frac{30}{3 c} = \frac{10}{c} \][/tex]
So, the value of [tex]\( x \)[/tex] in the equation is [tex]\( \frac{10}{c} \)[/tex].
