Answer :
To determine the amount of substance in 15 grams of [tex]\( \text{CaCO}_3 \)[/tex], follow these steps:
1. Calculate the Molar Mass of [tex]\( \text{CaCO}_3 \)[/tex]:
- The components of [tex]\( \text{CaCO}_3 \)[/tex] each have the following molar masses:
- Calcium (Ca) = 40 g/mol
- Carbon (C) = 12 g/mol
- Oxygen (O) = 16 g/mol (there are 3 oxygen atoms in [tex]\( \text{CaCO}_3 \)[/tex])
- Sum these values to find the molar mass of [tex]\( \text{CaCO}_3 \)[/tex]:
[tex]\[ \text{Molar mass of } \text{CaCO}_3 = 40 + 12 + (3 \times 16) = 100 \text{ g/mol} \][/tex]
2. Determine the Number of Moles in 15 Grams of [tex]\( \text{CaCO}_3 \)[/tex]:
- Use the formula for moles, which is:
[tex]\[ \text{Moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \][/tex]
- Substituting the given values:
[tex]\[ \text{Moles of } \text{CaCO}_3 = \frac{15 \text{ g}}{100 \text{ g/mol}} = 0.15 \text{ mol} \][/tex]
So, the amount of substance in 15 grams of [tex]\( \text{CaCO}_3 \)[/tex] is [tex]\( \boxed{0.15 \text{ mol}} \)[/tex].
1. Calculate the Molar Mass of [tex]\( \text{CaCO}_3 \)[/tex]:
- The components of [tex]\( \text{CaCO}_3 \)[/tex] each have the following molar masses:
- Calcium (Ca) = 40 g/mol
- Carbon (C) = 12 g/mol
- Oxygen (O) = 16 g/mol (there are 3 oxygen atoms in [tex]\( \text{CaCO}_3 \)[/tex])
- Sum these values to find the molar mass of [tex]\( \text{CaCO}_3 \)[/tex]:
[tex]\[ \text{Molar mass of } \text{CaCO}_3 = 40 + 12 + (3 \times 16) = 100 \text{ g/mol} \][/tex]
2. Determine the Number of Moles in 15 Grams of [tex]\( \text{CaCO}_3 \)[/tex]:
- Use the formula for moles, which is:
[tex]\[ \text{Moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \][/tex]
- Substituting the given values:
[tex]\[ \text{Moles of } \text{CaCO}_3 = \frac{15 \text{ g}}{100 \text{ g/mol}} = 0.15 \text{ mol} \][/tex]
So, the amount of substance in 15 grams of [tex]\( \text{CaCO}_3 \)[/tex] is [tex]\( \boxed{0.15 \text{ mol}} \)[/tex].
