```latex
\begin{tabular}{|c|c|}
\hline
[tex]$x$[/tex] & [tex]$f(x)$[/tex] \\
\hline
-1 & [tex]$2 \frac{2}{3}$[/tex] \\
\hline
0 & 2 \\
\hline
1 & 0 \\
\hline
2 & -6 \\
\hline
3 & -24 \\
\hline
\end{tabular}
```



Answer :

Let's work through the steps to determine the values of the function [tex]\( f(x) \)[/tex] for the given points.

Here is the data presented in tabular form:

[tex]\[ \begin{array}{|c|c|} \hline x & f(x) \\ \hline -1 & 2 \frac{2}{3} \\ \hline 0 & 2 \\ \hline 1 & 0 \\ \hline 2 & -6 \\ \hline 3 & -24 \\ \hline \end{array} \][/tex]

### Step-by-Step Solution:

1. Interpret the Fractional Value:
- For [tex]\( x = -1 \)[/tex], [tex]\( f(x) = 2 \frac{2}{3} \)[/tex].
- We need to convert the mixed number [tex]\( 2 \frac{2}{3} \)[/tex] into an improper fraction or a decimal.
- [tex]\( 2 \frac{2}{3} \)[/tex] can be written as [tex]\( 2 + \frac{2}{3} \)[/tex].
- Converting [tex]\( 2 \frac{2}{3} \)[/tex] to a decimal: [tex]\( 2 + \frac{2}{3} = 2 + 0.6666666666666666 \approx 2.6666666666666665 \)[/tex].

2. Write Down the Points:
Now we have the following points and their corresponding function values:
- For [tex]\( x = -1 \)[/tex], [tex]\( f(x) \approx 2.6666666666666665 \)[/tex].
- For [tex]\( x = 0 \)[/tex], [tex]\( f(x) = 2 \)[/tex].
- For [tex]\( x = 1 \)[/tex], [tex]\( f(x) = 0 \)[/tex].
- For [tex]\( x = 2 \)[/tex], [tex]\( f(x) = -6 \)[/tex].
- For [tex]\( x = 3 \)[/tex], [tex]\( f(x) = -24 \)[/tex].

3. Summarize the Points:
We can summarize the points in a compact form:

[tex]\[ \begin{align*} (-1, & \, 2.6666666666666665) \\ (0, & \, 2) \\ (1, & \, 0) \\ (2, & \, -6) \\ (3, & \, -24) \end{align*} \][/tex]

### Summary

The values of the function [tex]\( f(x) \)[/tex] for the given points are:

[tex]\[ [(-1, 2.6666666666666665), (0, 2), (1, 0), (2, -6), (3, -24)] \][/tex]

This tabulation helps us understand the behavior of the function at these specific points.

Other Questions