Which equation represents a line that passes through the two points in the table?

[tex]\[
\begin{tabular}{|c|c|}
\hline
$x$ & $y$ \\
\hline
3 & 3 \\
\hline
6 & 5 \\
\hline
\end{tabular}
\][/tex]

A. [tex]\( y + 3 = \frac{3}{2}(x + 3) \)[/tex]

B. [tex]\( y + 3 = \frac{2}{3}(x + 3) \)[/tex]

C. [tex]\( y - 3 = \frac{3}{2}(x - 3) \)[/tex]

D. [tex]\( y - 3 = \frac{2}{3}(x - 3) \)[/tex]



Answer :

To determine which of the given equations correctly represents the line passing through the points (3, 3) and (6, 5), we need to follow these steps:

1. Calculate the slope (m) of the line:

The slope of a line passing through two points [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex] is given by:
[tex]\[ m = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]
With the points [tex]\((3, 3)\)[/tex] and [tex]\((6, 5)\)[/tex]:
[tex]\[ m = \frac{5 - 3}{6 - 3} = \frac{2}{3} \][/tex]

2. Use the point-slope form to determine the equation:

The point-slope form of the equation of a line is:
[tex]\[ y - y_1 = m (x - x_1) \][/tex]
Substituting one of the points [tex]\((3, 3)\)[/tex] into the equation with the calculated slope [tex]\(m = \frac{2}{3}\)[/tex]:
[tex]\[ y - 3 = \frac{2}{3}(x - 3) \][/tex]

3. Compare with the given options:

Now, we'll check which of the given options matches the equation we derived:
[tex]\[ C. \quad y - 3 = \frac{3}{2}(x - 3) \quad \text{(Incorrect, wrong slope)} \][/tex]
[tex]\[ D. \quad y - 3 = \frac{2}{3}(x - 3) \quad \text{(Correct, matches our equation)} \][/tex]
[tex]\[ A. \quad y + 3 = \frac{3}{2}(x + 3) \quad \text{(Incorrect, wrong form and slope)} \][/tex]
[tex]\[ B. \quad y + 3 = \frac{2}{3}(x + 3) \quad \text{(Incorrect, wrong form)} \][/tex]

4. Conclusion:

The equation that correctly represents the line passing through the points (3, 3) and (6, 5) is:
[tex]\[ \boxed{y - 3 = \frac{2}{3}(x - 3)} \][/tex]

Thus, the correct option is:
[tex]\[ \boxed{\text{D}} \][/tex]

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