Answer :

Certainly! Let's solve the problem step by step.

1. Understand the problem: We are asked to multiply a binomial vector by a scalar and represent it as a column vector. The binomial vector in this case is [tex]\(\binom{2}{5}\)[/tex], and the scalar is [tex]\(3\)[/tex].

2. Identify the elements: The binomial vector has two elements: [tex]\(2\)[/tex] and [tex]\(5\)[/tex], and the scalar given is [tex]\(3\)[/tex].

3. Multiply the scalar with each element:
- Multiply the scalar [tex]\(3\)[/tex] with the first element of the binomial vector:
[tex]\[ 3 \times 2 = 6 \][/tex]
- Multiply the scalar [tex]\(3\)[/tex] with the second element of the binomial vector:
[tex]\[ 3 \times 5 = 15 \][/tex]

4. Formulate the column vector: To write this as a column vector, we place each of the resulting numbers in a vertical arrangement:
[tex]\[ \begin{pmatrix} 6 \\ 15 \end{pmatrix} \][/tex]

So, the scalar [tex]\(3\)[/tex] multiplied by the binomial vector [tex]\(\binom{2}{5}\)[/tex] written as a column vector is:
[tex]\[ \begin{pmatrix} 6 \\ 15 \end{pmatrix} \][/tex]

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