Answer :
To determine the real depth of the water reservoir, we'll use the concept of refraction, specifically the apparent depth versus real depth in a medium like water. When looking at an object submerged in water from above, the object appears closer to the surface than it really is due to the bending of light as it passes from water to air.
Given data:
- Apparent depth [tex]\( d_{apparent} = 1.0 \text{ m} \)[/tex]
- Refractive index of water [tex]\( n = 1.35 \)[/tex]
The relationship between the real depth [tex]\( d_{real} \)[/tex] and the apparent depth [tex]\( d_{apparent} \)[/tex] is given by:
[tex]\[ d_{real} = d_{apparent} \times n \][/tex]
Now substituting the known values:
[tex]\[ d_{real} = 1.0 \text{ m} \times 1.35 \][/tex]
Hence,
[tex]\[ d_{real} = 1.35 \text{ m} \][/tex]
So, the real depth of the reservoir is 1.35 meters.
Given data:
- Apparent depth [tex]\( d_{apparent} = 1.0 \text{ m} \)[/tex]
- Refractive index of water [tex]\( n = 1.35 \)[/tex]
The relationship between the real depth [tex]\( d_{real} \)[/tex] and the apparent depth [tex]\( d_{apparent} \)[/tex] is given by:
[tex]\[ d_{real} = d_{apparent} \times n \][/tex]
Now substituting the known values:
[tex]\[ d_{real} = 1.0 \text{ m} \times 1.35 \][/tex]
Hence,
[tex]\[ d_{real} = 1.35 \text{ m} \][/tex]
So, the real depth of the reservoir is 1.35 meters.
