Consider the derivation of [tex]\sin (2 x)[/tex].

[tex]\[
\begin{array}{|l|c|}
\hline
& \text{Step} \\
\hline
1. & \sin (2 x) = \sin (x + x) \\
\hline
2. & = \sin (x) \cos (x) + \cos (x) \sin (x) \\
\hline
3. & = (\sin (x) \cos (x))^2 \\
\hline
\end{array}
\][/tex]

Where is the error?

A. Step 2 should read [tex]=\cos (x) \cos (x) - \sin (x) \sin (x)[/tex].
B. Step 2 should read [tex]=\sin (x) \cos (x) - \cos (x) \sin (x)[/tex].
C. Step 3 should read [tex]=-2 \sin (x) \cos (x)[/tex].
D. Step 3 should read [tex]=2 \sin (x) \cos (x)[/tex].



Answer :

Let's analyze the correct derivation of [tex]\(\sin(2x)\)[/tex] using trigonometric identities.

### Step-by-Step Solution:

1. Expression for [tex]\(\sin(2x)\)[/tex]:
[tex]\[ \sin(2x) = \sin(x + x) \][/tex]
This is a correct starting point using the angle addition formula for sine.

2. Applying the Sine Angle Addition Formula:
According to the sine addition formula, [tex]\(\sin(a + b) = \sin(a)\cos(b) + \cos(a)\sin(b)\)[/tex]. Applying this to [tex]\(\sin(x + x)\)[/tex],
[tex]\[ \sin(x + x) = \sin(x)\cos(x) + \cos(x)\sin(x) \][/tex]
This simplifies to:
[tex]\[ \sin(2x) = \sin(x)\cos(x) + \cos(x)\sin(x) \][/tex]
Since [tex]\(\sin(x)\cos(x)\)[/tex] and [tex]\(\cos(x)\sin(x)\)[/tex] are the same, we have:
[tex]\[ \sin(2x) = 2\sin(x)\cos(x) \][/tex]
Therefore, Step 2 is correct as it stands.

3. Simplification of the Expression:
In the next step, we should derive the final simplified form.
[tex]\[ \sin(2x) \neq (\sin(x)\cos(x))^2 \][/tex]
The correct simplification we derived is:
[tex]\[ \sin(2x) = 2\sin(x)\cos(x) \][/tex]

### Identifying the Error:
1. The expression in Step 2 is correct as it uses [tex]\(\sin(x)\cos(x) + \cos(x)\sin(x)\)[/tex].
2. The primary error lies in Step 3. Instead of squaring the product [tex]\(\sin(x)\cos(x)\)[/tex], the correct derivative from Step 2 should be [tex]\(\sin(2x) = 2\sin(x)\cos(x)\)[/tex].

Therefore:
- Step 2 is correctly:
[tex]\[ \sin(x + x) = \sin(x)\cos(x) + \cos(x)\sin(x) \][/tex]
- Step 3 should be corrected as:
[tex]\[ \sin(2x) = 2\sin(x)\cos(x) \][/tex]

### Conclusion:
The correct choice indicating where the error is, corresponds to:
Step 3 should read [tex]\( = 2 \sin(x) \cos(x) \)[/tex].

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