Answer :
To determine the electric force [tex]\( F \)[/tex] felt by a charge [tex]\( q \)[/tex] placed in an electric field [tex]\( E \)[/tex], we can use the formula:
[tex]\[ F = qE \][/tex]
Given:
- The charge [tex]\( q \)[/tex] is [tex]\( +0.638 \, \text{C} \)[/tex]
- The electric field [tex]\( E \)[/tex] is [tex]\( 27.4 \, \text{N/C} \)[/tex] to the right
Substitute the values into the formula:
[tex]\[ F = (+0.638 \, \text{C}) \times (27.4 \, \text{N/C}) \][/tex]
Multiply these values together:
[tex]\[ F = 0.638 \times 27.4 \][/tex]
[tex]\[ F = 17.4812 \, \text{N} \][/tex]
The direction of the electric force is determined by the direction of the electric field and the sign of the charge:
- Since the electric field is to the right and the charge is positive, the force will also be to the right.
Therefore, the electric force felt by the charge is:
[tex]\[ F = +17.4812 \, \text{N} \][/tex]
The positive sign indicates that the direction of the force is to the right.
[tex]\[ F = qE \][/tex]
Given:
- The charge [tex]\( q \)[/tex] is [tex]\( +0.638 \, \text{C} \)[/tex]
- The electric field [tex]\( E \)[/tex] is [tex]\( 27.4 \, \text{N/C} \)[/tex] to the right
Substitute the values into the formula:
[tex]\[ F = (+0.638 \, \text{C}) \times (27.4 \, \text{N/C}) \][/tex]
Multiply these values together:
[tex]\[ F = 0.638 \times 27.4 \][/tex]
[tex]\[ F = 17.4812 \, \text{N} \][/tex]
The direction of the electric force is determined by the direction of the electric field and the sign of the charge:
- Since the electric field is to the right and the charge is positive, the force will also be to the right.
Therefore, the electric force felt by the charge is:
[tex]\[ F = +17.4812 \, \text{N} \][/tex]
The positive sign indicates that the direction of the force is to the right.
