13-05-2014
Chemistry

Answered

The oxygen saturation of a lake is found by dividing the amount of dissolved oxygen the lake water currently hasper liter by the dissolved oxygen capacity per liter of the water, and then converting that number into a percent. If the lake currently has 7.4 milligrams of dissolved oxygen per liter of water and the dissolved oxygen capacityis 9.4 milligrams per liter, what is the oxygen saturation level of the lake, to the nearest percent? Please help me with this one ;(

Answer :

13-05-2014

[tex] \frac{7.4}{9.4}*100\%= \frac{7.4*100}{9.4}\%= \frac{740}{9.4}\%\approx78.72\%\approx79\%[/tex]

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