Answer :

[tex]a^{log_ab}=b\\and\\log_ab^c=c\cdot log_ab\\\\\\10^{-10log3}=10^{log3^{-10}}=3^{-10}\\\\\\3^{-10}=\frac{1}{3^{10}}=\frac{1}{59\ 049}[/tex]

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