Answer :

Ryan2
[tex]9x^2-4y^2-24y-72=0\\ \\ 9x^2-4y^2-24y=72\\ \\ 9x^2-(4y^2+24y+36)=72-36\\ \\ 9x^2-4(y+3)^2=36\\ \\ \frac{9x^2}{36}-\frac{4(y+3)^2}{36}=\frac{36}{36}\\ \\ \boxed{\frac{x^2}{4}-\frac{(y+3)^2}{9}=1}[/tex]

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