Answer :

AL2006
The smaller number is 'x' .
The larger number is (x+ 20)

Their sum is [ x + (x + 20 ]

2x + 20 = 44

Subtract 20 from each side:

2x = 24

Divide each side by 2 :

x = 12
and
x + 20 = 32
Let the numebrs be x and y.

x + y = 44
x = y + 20

Substituting the value of x,

(y + 20) + y = 44

2y + 20 = 44
2y = 24
y = 12.

x = y + 20
x = 12+ 20

Thus, x = 32.

Thus, the two numbers are 32 and 12.

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