Answer :
[tex]long : \ l = \frac{4}{9} \ m \\ wide : \ w= \frac{4}{5} \ m \\ \\ Area =l \cdot w \\ \\Area =\frac{4}{9}\cdot \frac{4}{5}=\frac{16}{45} \ m^2[/tex]
[tex]Area=long\ \cdot\ wide= \frac{4}{9} \ [m]\ \cdot\ \frac{4}{5} \ [m]= \frac{16}{45} \ [m^2]\approx0.36\ [m^2]\\\\Ans.\ the\ area\ is\ \ \ \frac{16}{45} \ m^2[/tex]
