Answer :

[tex](x-2)(x+6)=\\ x^2+6x-2x-12=\\ x^2+4x-12[/tex]
[tex]roots\ are\ 2\ and\ -6\ and\ a=1\ then:\\\\1(x-2)(x+6)=0\\\\x\cdot x+x\cdot6-2\cdot x-2\cdot6=0\\\\x^2+6x-2x-12=0\\\\x^2+4x-12=0[/tex]

Other Questions