Answer :
[tex]a= \frac{7-2}{101} = \frac{5}{101} \\\\x_1=2+a=2 \frac{5}{101}\\\\x_2=2+2a=2 \frac{10}{101}\\\\x_3= 2+3a=2 \frac{15}{101}\\\\....\\\\x_{98}=7-3a=7- \frac{15}{101}=6 \frac{86}{101}\\\\x_{99}=7-2a=7- \frac{10}{101}=6 \frac{91}{101}\\\\x_{100}=7-a=7- \frac{5}{101}=6 \frac{96}{101}[/tex]
My view is that between any two rational numbers, there are
an infinite number of other rational numbers.
That's my view and I'm sticking to it.
an infinite number of other rational numbers.
That's my view and I'm sticking to it.
