A turntable is designed to acquire an angular velocity of 32.4 rev/s in 0.5 s, starting from rest.
Find the average angular acceleration of the turntable during the 0.5 s period.
Answer in units of rad/s2
Well, the acceleration is the difference of speeds divided by the time period. [tex]\frac{32.4}{0.5}=64.8rev/s^2[/tex]. One rev/s is [tex]2\pi rad/s^2[/tex], so our final result is [tex]64.8*2\pi=407.15rad/s^2[/tex].
