Answer :
[tex]y=\frac{1}{2}log(x+1)-log(2x+10)\\\\y\ intercept\ for\ x=0:\\\\\frac{1}{2}log(0+1)-log(2\cdot0+10)=\frac{1}{2}log1-log10=\frac{1}{2}\cdot0-1=-1\\\\Answer:y=-1,\ the\ point\ is\ (0;-1).[/tex]
y = 1/2 log(x + 1) - log(2x + 10)
The y-intercept of any graph is the point where x=0.
y = 1/2 log(0 + 1) - log(0 +10)
y = 1/2 log(1) - log(10)
log(1) = 0
log(10) = 1
y = 1/2 (0) - 1
y = -1
That's all there is to it. I'll bet you totally froze when you saw all those logs.
The y-intercept of any graph is the point where x=0.
y = 1/2 log(0 + 1) - log(0 +10)
y = 1/2 log(1) - log(10)
log(1) = 0
log(10) = 1
y = 1/2 (0) - 1
y = -1
That's all there is to it. I'll bet you totally froze when you saw all those logs.
