Answer :
[tex](5,6)[/tex]
[tex]x=5 \\ y=6[/tex]
[tex]y=x+1[/tex]
[tex](6)=(5)+1[/tex]
[tex]6=6[/tex]
[tex]true[/tex]
[tex]x=5 \\ y=6[/tex]
[tex]y=x+1[/tex]
[tex](6)=(5)+1[/tex]
[tex]6=6[/tex]
[tex]true[/tex]
Has your class not learned how to check an answer to see if it's correct ? ! ?
Your equation is [ y = x + 1 ].
You want to know whether (5, 6) is A solution to the equation.
When you write (5, 6), that means "x=5 and y=6".
So put those numbers into the equation in place of 'x' and 'y'
and see if the equation is true after you do that.
(y) = (x) + 1
(6) = (5) + 1
Do you see 5+1 on the right side. That's 6.
So the equation says " 6 = 6 " . . . a true statement.
So (5, 6) is a solution of the equation.
It's not THE solution. There are an infinite number of solutions
to that equation. (5, 6) is one of them.
Your equation is [ y = x + 1 ].
You want to know whether (5, 6) is A solution to the equation.
When you write (5, 6), that means "x=5 and y=6".
So put those numbers into the equation in place of 'x' and 'y'
and see if the equation is true after you do that.
(y) = (x) + 1
(6) = (5) + 1
Do you see 5+1 on the right side. That's 6.
So the equation says " 6 = 6 " . . . a true statement.
So (5, 6) is a solution of the equation.
It's not THE solution. There are an infinite number of solutions
to that equation. (5, 6) is one of them.
