Answer :
Sure. Why not ?
-- The 6 and the 11 can cover the 13 with some left over.
-- The 6 and the 13 can cover the 11 with some left over.
-- The 11 and the 13 can cover the 6 with a lot left over.
-- The 6 and the 11 can cover the 13 with some left over.
-- The 6 and the 13 can cover the 11 with some left over.
-- The 11 and the 13 can cover the 6 with a lot left over.
[tex]a=6 \ cm, \ \ b=11 \ cm, \ \ c= 13 \cm\\\\Formula. \\It \ is \ a \ eries \ of \ three \ inequalities:\\ a+b>c, \\a+c>b, \\ b+c>a.[/tex]
[tex]6+11 >13, \\6+13> 11, \\ 11+13> 6 \\ \\ 17 >13, \\19> 11, \\ 24> 6\\\\Answer: \ it \ is \ possible \ to \ construct \ a \ triangle \ with \ given \ sides[/tex]
[tex]6+11 >13, \\6+13> 11, \\ 11+13> 6 \\ \\ 17 >13, \\19> 11, \\ 24> 6\\\\Answer: \ it \ is \ possible \ to \ construct \ a \ triangle \ with \ given \ sides[/tex]
