Answer :
[tex]f(x)=x^3-5x^2+4x+10\\
f(x)=x^3+x^2-6x^2-6x+10x+10\\
f(x)=x^2(x+1)-6x(x+1)+10(x+1)\\
f(x)=(x+1)(x^2-6x+10)\\\\
x+1=0\\
x=-1\\\\
x^2-6x+10=0\\
x^2-6x+9+1=0\\
(x-3)^2=-1\\
x-3=i \vee x-3=-i\\
x=3+i \vee x=3-i\\\\
x=\{-1,3-i,3+i\}[/tex]