Answer :
[tex](-2,2), \ \ \ (0,5)\\\\First \ find \ the \ slope \ of \ the \ line \ thru \ the \ points \: \\ \\ m= \frac{y_{2}-y_{1}}{x_{2}-x_{1} } \\ \\m=\frac{ 5-2}{0+2} = \frac{3}{2} \\ \\ Use \ point \ form \ of \ a \ line\ with \ one \ point: \\ \\ y-y_{1} =m(x-x _{1})\\\\m=\frac{3}{2}, \ \ x_{1}=-2, \ \ y_{1}=2 \\ \\y- 2 = \frac{3}{2} (x+2)\\\\y=\frac{3}{2}x +3+2 \\ \\y=\frac{3}{2}x + 5[/tex]
