Answer :
pH = 3.83 = - log [H+] to base 10
So [H+] = 10^ -3.83 = 1.48 * 10^-4 moles
[H+] [OH-] = 10^-14
So [OH-] = 6.756 * 10^-11 moles
So Salt formation will be : 6.756 * 10^-11 moles
So [H+] = 10^ -3.83 = 1.48 * 10^-4 moles
[H+] [OH-] = 10^-14
So [OH-] = 6.756 * 10^-11 moles
So Salt formation will be : 6.756 * 10^-11 moles
