Answer :

[tex](4;-2);\ (-8;\ 6)\\\\the\ midpoint:\left(\frac{4+(-8)}{2};\ \frac{-2+6}{2}\right)\to\left(\frac{4-8}{2};\ \frac{4}{2}\right)\to\left(\frac{-4}{2};\ \frac{4}{2}\right)\to(-2;\ 2)[/tex]
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Answer:

(-2, 2)

Step-by-step explanation:

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