Answer :
We aplly the rules of the module:
[tex]|x| = \left \{ {{-x \ ; \ \ x<0} \\ \atop {x \ ; \ x \geq 0}} \right.[/tex]
So, we have:
[tex]A) |-8| < |8| \\\\ 8 < 8 \to\to False \to\boxed{8=8} \\\\ B) |-2| >1 \\\\ \boxed{\boxed{2>1}} \to\to True \\\\ C) |-7|=-7 \\\\ 7=-7 \to\to False \\\\ D)|12|>|-15| \\\\ 12>15 \to\to False[/tex]
The right answer is variant B.
[tex]|x| = \left \{ {{-x \ ; \ \ x<0} \\ \atop {x \ ; \ x \geq 0}} \right.[/tex]
So, we have:
[tex]A) |-8| < |8| \\\\ 8 < 8 \to\to False \to\boxed{8=8} \\\\ B) |-2| >1 \\\\ \boxed{\boxed{2>1}} \to\to True \\\\ C) |-7|=-7 \\\\ 7=-7 \to\to False \\\\ D)|12|>|-15| \\\\ 12>15 \to\to False[/tex]
The right answer is variant B.
Letter B is true because the absolute value of -2 is 2. The mouth is opened towards the 2 and |-2| is greater than 1.
It is just as if saying 2 is greater than 1
It is just as if saying 2 is greater than 1
