Answer :
This is good.
Using the general format: y -y1 = m(x-x1), format of a slope and a point.
(x1, y1) = (8,10)
y -10 = (3/4)*(x-8)
y -10 = 3x/4 -6 Multiply through by 4.
4y -40 = 3x -24
4y = 3x -24 + 40
4y = 3x + 16.
So equation of the line is: 4y = 3x + 16.
Using the general format: y -y1 = m(x-x1), format of a slope and a point.
(x1, y1) = (8,10)
y -10 = (3/4)*(x-8)
y -10 = 3x/4 -6 Multiply through by 4.
4y -40 = 3x -24
4y = 3x -24 + 40
4y = 3x + 16.
So equation of the line is: 4y = 3x + 16.
