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Which equation are equations for the line shown

A y-3=-1/2(x-4)

B y-4=1/2(x-3)

C y-3=1/2(x+1)

D y-1=1/2(x+3)
The points to draw line on the graph is (-3,1) and (3,4) please help



Answer :

The answer would be B and Dbecause if you use the formula y-b=m(x-a) where m is the gradient, and (a,b) are a point on the line.
So m= (y2-y1)/(x2-x1) = (4-1)/(3-(-3)) = 3/6 = 1/2
And by using (a,b) this tells us that a=-3 when b=1 AND a=3 when b=4
Therefore the full equation must be either
y-1=1/2(x+3) AND
y-4=1/2(x-3)
Hope this helps :-)

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