ismahmuslimah ismahmuslimah

26-11-2014
Mathematics

Answered

Himpunan penyelesaian dari pertidaksamaan | 2x + 1| ≤ 3 adalah.....
a. { -1 ≤ x ≤3 }
b. { -2 ≤ x ≤ 2}
c. { -2 ≤ x ≤ 1 }
d. { -1 ≤ x ≤ 1 }
e. { 0 ≤ x ≤ 1 }
Tolong caranya...

Answer :

konrad509 konrad509

26-11-2014

[tex]| 2x + 1| \leq3 \\ 2x+1\leq3\wedge2x+1\geq-3\\ 2x\leq2 \wedge 2x\geq-4\\ x\leq1 \wedge x\geq-2\\ -2\leq x \leq1 \Rightarrow C [/tex]

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