Answer :
We have such problem
[tex] \frac{3}{18}: \frac{5}{8} [/tex]
If we want divide 2 fraction we can multiply first times inverse of second fraction, so
[tex] \frac{3}{18} : \frac{5}{8}= \frac{3}{18} * \frac{8}{5}= \frac{3*8}{18*5}= \frac{24}{90}= \frac{24:6}{90:6}= \frac{4}{15} [/tex] - its the answer
[tex] \frac{3}{18}: \frac{5}{8} [/tex]
If we want divide 2 fraction we can multiply first times inverse of second fraction, so
[tex] \frac{3}{18} : \frac{5}{8}= \frac{3}{18} * \frac{8}{5}= \frac{3*8}{18*5}= \frac{24}{90}= \frac{24:6}{90:6}= \frac{4}{15} [/tex] - its the answer
[tex] \frac{3}{18} [/tex]÷[tex] \frac{5}{8} [/tex]
When dividing fractions, you flip the second fraction
[tex] \frac{3}{18} * \frac{8}{5} [/tex]=[tex] \frac{24}{90} [/tex]
Then you simplify by finding common factors for both the numerator and denominator
[tex] \frac{24}{90} [/tex] can be divided by 2 but you have to divide both the numerator and denominator
[tex] \frac{24}{90} [/tex]÷[tex] \frac{2}{2} [/tex]⇒[tex] \frac{12}{45} [/tex]
3 is a factor for both the numerator and denominator so it can be used to divide them
[tex] \frac{12}{45} [/tex]÷[tex] \frac{3}{3} [/tex]⇒[tex] \frac{4}{15} [/tex]
[tex] \frac{4}{15} is your answer[/tex]
When dividing fractions, you flip the second fraction
[tex] \frac{3}{18} * \frac{8}{5} [/tex]=[tex] \frac{24}{90} [/tex]
Then you simplify by finding common factors for both the numerator and denominator
[tex] \frac{24}{90} [/tex] can be divided by 2 but you have to divide both the numerator and denominator
[tex] \frac{24}{90} [/tex]÷[tex] \frac{2}{2} [/tex]⇒[tex] \frac{12}{45} [/tex]
3 is a factor for both the numerator and denominator so it can be used to divide them
[tex] \frac{12}{45} [/tex]÷[tex] \frac{3}{3} [/tex]⇒[tex] \frac{4}{15} [/tex]
[tex] \frac{4}{15} is your answer[/tex]
