Answer :
x - the first integer
x+2 - the second integer
x+4 - the third integer
[tex]x+x+2+x+4=141 \\ 3x+6=141 \\ 3x=141-6 \\ 3x=135 \\ x=\frac{135}{3} \\ x=45 \\ \\ x+2=45+2=47 \\ x+4=45+4=49[/tex]
The integers are: 45, 47, 49.
x+2 - the second integer
x+4 - the third integer
[tex]x+x+2+x+4=141 \\ 3x+6=141 \\ 3x=141-6 \\ 3x=135 \\ x=\frac{135}{3} \\ x=45 \\ \\ x+2=45+2=47 \\ x+4=45+4=49[/tex]
The integers are: 45, 47, 49.
