Answer :
Let's consider a, a+1 and a+2 the three consecutives integers
a+(a+1)+(a+2)=171
3a+3=171
3a=171-3
3a=168
a=56
So the numbers are: 56, 57, 58.
Check: 56+57+58=171
a+(a+1)+(a+2)=171
3a+3=171
3a=171-3
3a=168
a=56
So the numbers are: 56, 57, 58.
Check: 56+57+58=171
Answer:
56,57,58
Step-by-step explanation:
a+(a+1)+(a+2)=171
3a+3=171
3a=171-3
3a=168
a=56
So the numbers are: 56, 57, 58.
Check: 56+57+58=171
