Answer :
[tex]3x-2y=9 \\
y=2x-7 \\ \\
\hbox{substitute 2x-7 for y in the 1st equation:} \\
3x-2(2x-7)=9 \\
3x-4x+14=9 \\
-x+14=9 \ \ \ |-14 \\
-x=-5 \ \ \ |\times (-1) \\
x=5 \\ \\
y=2x-7=2 \times 5-7=10-7=3 \\ \\
\boxed{(x,y)=(5,3)}[/tex]