Answer :

[tex]\alpha^\frac{4}{3}\cdot\alpha^\frac{2}{3}\\------------\\use:a^n\cdot a^m=a^{n+m}\\------------\\=\alpha^{\frac{4}{3}+\frac{2}{3}}=\alpha^\frac{4+2}{3}=\alpha^\frac{6}{3}=\boxed{\alpha^2}[/tex]
a^⁴/₃ · a^²/₃ = a^(⁴/₃ ⁺ ²/₃) = a^⁶/₃ = a²

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