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Please help, i am very stuck
We wish to determine the moles of CO produced when 50.0 mL of 2.0 M
HCL reacts with excess Na2CO3.
In the previous step, you determined
0.10 mol HI react.
How many moles of CO2 form during the reaction?



Answer :

Answer:

Explanation: To determine the moles of HCl present in 50.0 mL of 2.0 M HCl, we can use the formula:

M = moles/volume

where M is the molarity of the solution, moles is the number of moles of solute, and volume is the volume of the solution in liters.

First, we need to convert the volume of the solution from milliliters to liters:

50.0 mL = 0.0500 L

Now we can use the formula to find the number of moles of HCl:

M = moles/volume

2.0 M = moles/0.0500 L

moles = 2.0 M * 0.0500 L

moles = 0.100 mol

Therefore, there are 0.100 moles of HCl present in 50.0 mL of 2.0 M HCl.

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