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A brick has a mass of 4.0 kg and the Earth has a mass of [tex]\(6.0 \times 10^{27} \text{g}\)[/tex].

Use this information to answer the question below. Ensure your answer has the correct number of significant digits.

What is the mass of 1 mole of bricks?



Answer :

Sure! Let's solve the problem step-by-step.

### Step 1: Understand the Problem
We have:
1. The mass of a single brick: [tex]\(4.0 \, \text{kg}\)[/tex]
2. Avogadro's number: [tex]\(6.02214076 \times 10^{23}\)[/tex]

We need to calculate the mass of 1 mole of bricks.

### Step 2: Conversion
Avogadro's number represents the number of entities (in this case, bricks) in one mole. So if each brick has a mass of [tex]\(4.0 \, \text{kg}\)[/tex], the mass of one mole of bricks would be the mass of one brick multiplied by Avogadro's number.

### Step 3: Calculation
- Mass of one brick: [tex]\(4.0 \, \text{kg}\)[/tex]
- Number of bricks in one mole (Avogadro's number): [tex]\(6.02214076 \times 10^{23}\)[/tex]

#### Multiply these two values:
[tex]\[ \text{Mass of 1 mole of bricks} = 4.0 \, \text{kg} \times 6.02214076 \times 10^{23} \][/tex]

[tex]\[ \text{Mass of 1 mole of bricks} = 2.408856304 \times 10^{24} \, \text{kg} \][/tex]

### Step 4: Significant Figures
The given data (mass of the brick being [tex]\(4.0 \, \text{kg}\)[/tex]) has 2 significant figures, therefore our final answer should be expressed to 2 significant figures as well.

Hence, the mass of 1 mole of bricks, to the correct number of significant digits, is:
[tex]\[ \text{Mass of 1 mole of bricks} = 2.4 \times 10^{24} \, \text{kg} \][/tex]

So, the mass of 1 mole of bricks is [tex]\(2.4 \times 10^{24} \, \text{kg}\)[/tex].

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