Answer :
Sure! Let's go through each question step-by-step.
### Question 8: Finding the Other Decimal
The problem states:
- The product of two decimals is 131.58.
- One of the decimals is 21.5.
We are asked to find the other decimal.
Step-by-Step Solution:
1. The formula for the product of two numbers \( a \times b = c \).
2. Here, \( c = 131.58 \) and \( a = 21.5 \).
3. We need to find \( b \). So, rearrange the formula to solve for \( b \):
[tex]\[ b = \frac{c}{a} \][/tex]
4. Plug in the values:
[tex]\[ b = \frac{131.58}{21.5} \][/tex]
5. Simplifying this, we get:
[tex]\[ b \approx 6.12 \][/tex]
So, the other decimal is approximately 6.12.
### Question 9: Money from Selling Milk
The problem states:
- A milkman sells 42 liters of milk.
- Each liter is sold for ₹25.50.
We are asked to calculate the total amount of money he will get.
Step-by-Step Solution:
1. To find the total money, use the formula:
[tex]\[ \text{Total Money} = \text{Number of Liters} \times \text{Price per Liter} \][/tex]
2. Here, the number of liters = 42 and the price per liter = ₹25.50.
3. Plug in the values:
[tex]\[ \text{Total Money} = 42 \times 25.50 \][/tex]
4. Simplifying this, we get:
[tex]\[ \text{Total Money} = 1071 \][/tex]
So, the milkman will get ₹1071 from selling the milk.
### Question 10: Finding the Thickness of One Notebook
The problem states:
- The total thickness of 15 notebooks is 22.5 cm.
We are asked to find the thickness of one notebook.
Step-by-Step Solution:
1. To find the thickness of one notebook, use the formula:
[tex]\[ \text{Thickness per Notebook} = \frac{\text{Total Thickness}}{\text{Number of Notebooks}} \][/tex]
2. Here, the total thickness = 22.5 cm and the number of notebooks = 15.
3. Plug in the values:
[tex]\[ \text{Thickness per Notebook} = \frac{22.5}{15} \][/tex]
4. Simplifying this, we get:
[tex]\[ \text{Thickness per Notebook} = 1.5 \][/tex]
So, the thickness of one notebook is 1.5 cm.
In summary,
1. The other decimal is approximately 6.12.
2. The milkman will get ₹1071 from selling the milk.
3. The thickness of one notebook is 1.5 cm.
### Question 8: Finding the Other Decimal
The problem states:
- The product of two decimals is 131.58.
- One of the decimals is 21.5.
We are asked to find the other decimal.
Step-by-Step Solution:
1. The formula for the product of two numbers \( a \times b = c \).
2. Here, \( c = 131.58 \) and \( a = 21.5 \).
3. We need to find \( b \). So, rearrange the formula to solve for \( b \):
[tex]\[ b = \frac{c}{a} \][/tex]
4. Plug in the values:
[tex]\[ b = \frac{131.58}{21.5} \][/tex]
5. Simplifying this, we get:
[tex]\[ b \approx 6.12 \][/tex]
So, the other decimal is approximately 6.12.
### Question 9: Money from Selling Milk
The problem states:
- A milkman sells 42 liters of milk.
- Each liter is sold for ₹25.50.
We are asked to calculate the total amount of money he will get.
Step-by-Step Solution:
1. To find the total money, use the formula:
[tex]\[ \text{Total Money} = \text{Number of Liters} \times \text{Price per Liter} \][/tex]
2. Here, the number of liters = 42 and the price per liter = ₹25.50.
3. Plug in the values:
[tex]\[ \text{Total Money} = 42 \times 25.50 \][/tex]
4. Simplifying this, we get:
[tex]\[ \text{Total Money} = 1071 \][/tex]
So, the milkman will get ₹1071 from selling the milk.
### Question 10: Finding the Thickness of One Notebook
The problem states:
- The total thickness of 15 notebooks is 22.5 cm.
We are asked to find the thickness of one notebook.
Step-by-Step Solution:
1. To find the thickness of one notebook, use the formula:
[tex]\[ \text{Thickness per Notebook} = \frac{\text{Total Thickness}}{\text{Number of Notebooks}} \][/tex]
2. Here, the total thickness = 22.5 cm and the number of notebooks = 15.
3. Plug in the values:
[tex]\[ \text{Thickness per Notebook} = \frac{22.5}{15} \][/tex]
4. Simplifying this, we get:
[tex]\[ \text{Thickness per Notebook} = 1.5 \][/tex]
So, the thickness of one notebook is 1.5 cm.
In summary,
1. The other decimal is approximately 6.12.
2. The milkman will get ₹1071 from selling the milk.
3. The thickness of one notebook is 1.5 cm.
