Answer :
[tex](m+2)(m+3)=(m+2)(m-2)\\\\m^2+3m+2m+6=m^2-4\\\\m^2-m^2+5m=-4-6\\\\5m=-10\ \ \ \ /:5\\\\m=-2[/tex]
The first time you look at this, you would think that you can just cancel the
(m+2) off of each side. But then you're left with (m+3) = (m-2), and there's
no solution for this. So you have to go back and do it the hard way.
Expand each side of the equation. (Clear the parentheses.)
m² + 5m + 6 = m² - 4
Subtract m² from each side:
5m + 6 = -4
Subtract 6 from each side:
5m = -10
Divide each side by 5:
m = -2
(m+2) off of each side. But then you're left with (m+3) = (m-2), and there's
no solution for this. So you have to go back and do it the hard way.
Expand each side of the equation. (Clear the parentheses.)
m² + 5m + 6 = m² - 4
Subtract m² from each side:
5m + 6 = -4
Subtract 6 from each side:
5m = -10
Divide each side by 5:
m = -2
